I have an unclear xml and process it with python lxml module. I want replace all \n in content with space before any processing, how can I do this work for text of all elements.

edit my xml example:

<root><a> dsdfs\n dsf\n sdf\n</a><bds> <d>sdf\n\n\n\n\n\n</d><d>sdf\n\n\nsdf\nsdf\n\n</d></bds>................
</root>

and i wan't to get this in output when i print ittertext:

root = #get root element
for i in root.ittertext():print idsdfs  dsf  sdf
dsdfs  dsf  sdf
sdf  nsdf sdf  

Below code will parse the xml into a string, then replace \n with space and then write to a new xml file. You can do other processing in between, depending what exactly you want to do.

from lxml import etree 
tree = etree.parse('some.xml') 
root = tree.getroot()
# Get the whole XML content as  string
xml_in_str = etree.tostring(root)# Replace all \n with space
new_xml_data = xml_in_str.replace(r'\n', ' ')# Do the processing with the new_xml_data string which is formatted# Maybe also write to a new XML file, without the \n
with open('newxml.xml', 'w') as f:f.write(new_xml_data)

some.xml looks like:

<root><a> dsdfs\n dsf\n sdf\n</a><bds> <d>sdf\n\n\n\n\n\n</d><d>sdf\n\n\nsdf\nsdf\n\n</d></bds><bds> <d>sdf\n\n\n\n\n\n</d><d>sdf\n\n\nsdf\nsdf\n\n</d></bds><bds> <d>sdf\n\n\n\n\n\n</d><d>sdf\n\n\nsdf\nsdf\n\n</d></bds>
</root>

newxml.xml looks like:

<root><a> dsdfs  dsf  sdf </a><bds> <d>sdf      </d><d>sdf   sdf sdf  </d></bds><bds> <d>sdf      </d><d>sdf   sdf sdf  </d></bds><bds> <d>sdf      </d><d>sdf   sdf sdf  </d></bds>
</root>