I'm struggling to understand Function closures properly. For example in the code below I am unclear as to how the function knows that in the statement times3(2) that x=2? Also, after reading documentations I still can't fully understand the purpose of closures.

def make_multiplier_of(n):def multiplier(x):return x * nreturn multipliertimes3 = make_multiplier_of(3)
times3(2) #How does the function know that x=2 here?

Thanks a lot

When you are calling make_multiplier_of(3), the function is returning multiplier such that

def multiplier(x):return x*3

So times3 = make_multipiler(3) is assigning this particular multiplier function to times3. The same way that when you are doing myLength=len, myLength is the len function and you can call myLength("foo")

times3 is thus this multiplier function. So when you times3(2), you are doing (this particular) multiplier(2)