I have a dataframe that looks like

LineEntry: [0x0000000002758261-0x0000000002758268): /a/b/c:7921:14
LineEntry: [0x0000000002756945-0x0000000002756960): /f/b/c:6545:10
LineEntry: [0x00000000027562c9-0x00000000027562d0): /k/b/c
LineEntry: [0x00000000027562c9-0x00000000027562d0): /c/d/f
....
....

I am interested only in strings that look like the first two entries( i.e 5 strings after before and after colon delimiter) and extract the last two strings before and after last colon ( Ex:7921, 14)

After filtering above, the dataframe should like
LineEntry: [0x0000000002758261-0x0000000002758268): /a/b/c:7921:14
LineEntry: [0x0000000002756945-0x0000000002756960): /f/b/c:6545:10

I have tried res = re.split(":", df ) and use res[3] and res[4] to extract last 2 strings before and after colon , but I get errors for 3 and 4th type of lines as above.

Any effective ways of filtering dataframe entries that exactly looks like the first two line entries?

I'm assuming that the example data given is a column in a dataframe and you want to filter for those rows that end with a digit (number). You can use str.isdigit() for this, like below:

arr = df['your_col_name'].to_list()
[x for x in arr if x[-1].isdigit()] # return just the column values as list

Output:

['LineEntry: [0x0000000002758261-0x0000000002758268): /a/b/c:7921:14','LineEntry: [0x0000000002756945-0x0000000002756960): /f/b/c:6545:10']

If instead, you want to filter the data frame:

df = df.reset_index() # this assumes your index is range(0, nrows)
arr = df['your_col_name'].to_list()
filter = [i for i,x in enumerate(arr) if x[-1].isdigit()]
df.iloc[filter,:] 

Output:

                                       your_col_name
0  LineEntry: [0x0000000002758261-0x0000000002758...
1  LineEntry: [0x0000000002756945-0x0000000002756...

Another option is to use re.search(r'\d+$', string) but this regex does something similar (searches if string ends with a digit)