Python Program to check if a number is armstrong or not is not working, what am I doing wrong?

2024/10/8 2:24:50
n=int(input("Enter a Number: "))
x=0
y=0
z=0while(n>0):x=n%10y=x**3z=z+yn=n//10print (z) #The z here is the same value which I enter, yet it doesn't work.
#If I enter 407 as n, z becomes (4^3)+(0^3)+(7^3) which is 407if (z==n): #But even when 407==407, it just wont print the bottom statementprint ("The number is Armstrong")
else:print ("The number isn't Armstrong")#it prints that it isn't an Armstrong number
Answer

After the while loop, n already became 4//10 which is 0, so it'll never equal z which is 407.

You will want to keep a copy of the original input for comparison.

As a general advice, use a debugger or at least print() your objects to see where the assignments went wrong.

https://en.xdnf.cn/q/118752.html

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