How can I list all 1st row values in an Excel spreadsheet using OpenPyXL?

2024/11/17 17:31:18

Using the OpenPyXL module with Python 3.5, I was able to figure out how many columns there are in a spreadsheet with:

In [1]: sheet.max_column
Out [1]: 4

Then I was able to list the values in each of the 4 cells with:

In [2]: for rowOfCellObjects in sheet['A1':'D1']:for cellObj in rowOfCellObjects:print(cellObj.coordinate, cellObj.value)
Out [2]: A1 Dog, B1 Cat, C1 Hamster, D1 Bigger Dog

But is there a way to skip the first step and simply list the values for x number of columns?

I wouldn't have known to iterate over ['A1':'D1] if I didn't know how many columns there were. If there were say 200 columns it would be a time waster to calculate the 200th letter/number after ['A1'].

Answer

If you need to iterate through all the rows or columns of a file, you can instead use the openpyxl.worksheet.Worksheet.rows() property, or the openpyxl.worksheet.Worksheet.columns() property.

See Manipulating a workbook in memory.

https://en.xdnf.cn/q/118778.html

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