My Goal - To list only 5 entries when using OS walk. So far I have only been able to get a list of everything that I find using OS.Walk or only list one entry. (By using the return function)

My code: import os import subprocess

def playmusic(name):for root, dirs, files in os.walk('E:\\', followlinks=True):for file in files:if name in file:vlc='C:/Program Files/VideoLAN/VLC/vlc.exe'music=str(os.path.join(root,file))print(music)#subprocess.Popen([vlc, music])#returnprint("Finish")input()
try:s=raw_input("name: ")playmusic(s)
except Exception as e:print(e)print("Error")

The Results:

=== RESTART: C:\Users\VGMPC2\Documents\testing scripts\search and print.py ===
name: test
E:\Nes\Jordan Vs Bird\3 Point Contest.mp4
E:\Nes\Jordan Vs Bird\Slam Dunk Contest.mp4
E:\playlist\Action&Adventuretest.xspf
E:\playlist\schedule test 2.xspf
E:\Snes\Lufia II\The Greatest Thieves.mp4
E:\Symbolic playlists\Nintendo Generation\3 Point Contest.mp4
E:\Symbolic playlists\Nintendo Generation\Slam Dunk Contest.mp4
Finish

If there is any way to only show 5 instead of the whole list that would be great! I tried using len() but I was having trouble figuring out how to use it with the os walk search. I would say the biggest thing is the music=str(os.path.join(root,file)) as that does the search I believe.

Any ideas would be appreciated. Thank you for your time,

Try this:

def playmusic(name):for root, dirs, files in os.walk('E:\\', followlinks=True):for file in files[0:5]: #You show the first five onlyif name in file:vlc='C:/Program Files/VideoLAN/VLC/vlc.exe'music=str(os.path.join(root,file))print(music)#subprocess.Popen([vlc, music])#returnprint("Finish")input()
try:s=raw_input("name: ")playmusic(s)
except Exception as e:print(e)print("Error")