How to split a list into chucks of different sizes specified by another list? [duplicate]

2024/11/17 4:29:51

I have an array I am trying to split into chunks of different sizes.

In the example below, loopN is are the chuck sizes. I have tried all sorts of ways to iterate through loopN, however can't figure it out. list is the array I am trying to split into chunks.

loopN = [2,3,1]
list = [1,2,3,4,5,6]for i in range(0, len(list), loopN):chunks.append(list[i:i+loopN])

The output I was looking for was [[1,2],[3,4,5],[6]].

How do I split the array into chucks of different sizes?

Answer

You can use itertools.islice to take slices of l according to the elements in loopN:

from itertools import isliceloopN = [2,3,1]
l = iter([1,2,3,4,5,6])[list(islice(l, i)) for i in loopN]
# [[1, 2], [3, 4, 5], [6]]

If you want to stick to list methods, following your approach, there are a few things that are wrong already spotted by @barmar. Note that the slice i:i+loopN doesn't really make sense. You cannot add an integer and a list.

You need to iterate over the values that will be used to slice l, so over loopN. Also you don't need ranges, just directly iterate over loopN, which is an iterable too, and keep track over the previous values you've iterated over, adding them on each iteration to move the slices forward.

https://en.xdnf.cn/q/119117.html

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