For a school task I need to display a nxn matrix depending on users input: heres an example:

0 0 0 0 1
0 0 0 1 0
0 0 1 0 0
0 1 0 0 0
1 0 0 0 0

(users input: 5)

And here is my code until now:

    n = int(input("please enter a number: "))for i in range( 1,n+1):for j in range(1,n+1):print(0, end = " ")print('\n')

So it only displays zero in my matrix, but how can I implement the one switching one position in each line?

• First, try to find the relation or pattern happend when there is '1' in matrix, you will find that if (row_number + column_number = n - 1) then there is '1'
• row=[] you will make empty list to add the values of each row in it, notice that you will put row=[] inside for row_number in range(n): to make empty list after finish each row.
• if row_number+column_number == n-1: this is the pattern happens when there is '1', so if condition is true there is 1 will be appended in the row, and if condition is false there is 0 will be appended in the row.
• print(*row) i use * to unpack the elements of list

n = int(input("please enter a number: "))for row_number in range(n):row = []for column_number in range(n):if row_number+column_number == n-1:row.append(1)else:row.append(0)print(*row)

Output

please enter a number: 5
0 0 0 0 1
0 0 0 1 0
0 0 1 0 0
0 1 0 0 0
1 0 0 0 0