Python: get the max value with the location above and below than the max

2024/7/7 6:08:42

If I have a dataframe like this,

index  User    Value  location1      1      1.0    4.5 2      1      1.5    5.23      1      3.0    7.04      1      2.5    7.55      2      1.0    11.56      2      1.25   14.17      2      2.0    13.08      2      3.5    14.09      3      2.0    2.410     3      3.5    4.311     3      1.0    5.412     3      3.0    5.313     4      1.0    11.014     4      3.0    12.3

How would I select the max VALUE for each user with the nearest neighbor (above and lower) location of the max location, and if there's only one nearest location of the max, retrieve them as well?

The final results should be like this,

index  User   Value  location 2      1      1.5    5.23      1      3.0    7.04      1      2.5    7.56      2      1.25   14.17      2      2.0    13.08      2      3.5    14.09      3      2.0    2.410     3      3.5    4.312     3      3.0    5.313     4      1.0    11.014     4      3.0    12.3
Answer
import pandas as pd# df = "your_data_frame"new_df = pd.DataFrame({"ID": [],"User": [],"Value": []})for user in sorted(list(set(df['User'].to_list()))):new_df = pd.concat([new_df, df[df['User'] == user].nlargest(3, 'location')])
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