Python If statement and logical operator issue [duplicate]

2024/7/7 7:00:41

I'm trying to create a small python program to emulate rolling a single die. My problem arises in that I want the program to accept both upper and lower-case 'Y' to trigger a re-roll. My program works when I accept either upper or lower case y but when I try to change the line

if usr == 'Y'

to

if usr == 'Y' or 'y'

creates a problem where it never enters the else statement, making the program never terminate.

import randomdef DiceRoll():number = random.randrange(1, 7, 1)print("Dice Roll: ", number)AskUser()returndef AskUser():usr = input("Roll Again? (Y/N) \n")if usr == 'Y':DiceRoll()else :print("Thank you for playing!")
returnDiceRoll()
Answer

You must do

if usr == 'Y' or usr == 'y'.

It is currently evaluating the statement 'y' as its own condition, and in this case 'y' always evaluates to true.

https://en.xdnf.cn/q/120046.html

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