Python program that rolls a fair die counts the number of rolls before a 6 shows up

2024/11/18 14:56:02
import randomsample_size = int(input("Enter the number of times you want me to roll the die: "))if (sample_size <=0):print("Please enter a positive number!")else:counter1 = 0counter2 = 0final = 0while (counter1<= sample_size):dice_value = random.randint(1,6)if ((dice_value) == 6):counter1 += 1else:counter2 +=1final = (counter2)/(sample_size)  # fixing indention print("Estimation of the expected number of rolls before pigging out: " + str(final))

Is the logic used here correct? It will repeat rolling a die till a one is rolled, while keeping track of the number of rolls it took before a one showed up. It gives a value of 0.85 when I run it for high values(500+)

Thanks

Answer
import randomwhile True:sample_size = int(input("Enter the number of times you want me to roll a die: "))if sample_size > 0:breakroll_with_6 = 0
roll_count = 0while roll_count < sample_size:roll_count += 1n = random.randint(1, 6)#print(n)if n == 6:roll_with_6 += 1print(f'Probability to get a 6 is = {roll_with_6/roll_count}')

One sample output:

Enter the number of times you want me to roll a dile: 10
Probability to get a 6 is = 0.2

Another sample output:

Enter the number of times you want me to roll a die: 1000000
Probability to get a 6 is = 0.167414
https://en.xdnf.cn/q/120066.html

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