How do you return a list of the matched item in string with regex? [duplicate]

2024/7/7 6:43:10

I made this simple functions that searches for emails in the source code of a page , the content is just the response taken from get request , now how do you return the matchs in findall as a list with out the \n or ant other unwanted strings

My goal is to get a list of all the matched strings (emails)

def find_emails(content):email_reg =  r"""[a-zA-Z0-9_.]+@+[a-zA-Z0-9]+.+[a-zA-Z0-9]*"""mail_lst = re.findall(email_reg , content)return mail_lst

when the program reaches this for loop i get the emails found in the regex but they are separated by \n and i get some random string in between the emails

I tried using brackets in my regex but this didn't make any difference

if __name__ == "__main__":res = find_emails(content)for item in res:print(item) 
Answer
import re

your regex is wrong , . matches all occurance

def find_emails(content):email_reg =  r"^[a-zA-Z0-9+_.-]+@[a-zA-Z0-9.-]+$"mail_lst = re.findall(email_reg , content)return mail_lstprint(find_emails("hiiii@asdasd.££$%%$com"))
print(find_emails("[email protected]"))
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