I am trying to output the binary representation of an negative number with the least bytes available each time.
Example:
-3 -> 101
-10 -> 10110
I am trying to output the binary representation of an negative number with the least bytes available each time.
Example:
-3 -> 101
-10 -> 10110
Here's a way to do this using the .bit_length
method of Python 3 integers. It also uses the string .format
method to do the integer to binary string conversion. This function returns a string starting with '0' for non-negative numbers so that they can be distinguished from negative numbers.
def twos_complement(n):m = n + 1 if n < 0 else nbitlen = 1 + m.bit_length()mask = (1 << bitlen) - 1return '{0:0{1}b}'.format(n & mask, bitlen)for i in (-10, -3, 0, 3, 10):print('{:3}: {}'.format(i, twos_complement(i)))print('- ' * 30)for i in range(-15, 16):print(i, twos_complement(i))
output
-10: 10110-3: 1010: 03: 01110: 01010
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
-15 10001
-14 10010
-13 10011
-12 10100
-11 10101
-10 10110
-9 10111
-8 1000
-7 1001
-6 1010
-5 1011
-4 100
-3 101
-2 10
-1 1
0 0
1 01
2 010
3 011
4 0100
5 0101
6 0110
7 0111
8 01000
9 01001
10 01010
11 01011
12 01100
13 01101
14 01110
15 01111
Python uses a modified form of two's complement to represent integers. Python integers have no size limit, so negative integers behave as if they have an infinite number of leading 1 bits, as explained in the Python Wiki article on Bitwise Operators.
The int.bit_length
method tells us the minimum number of bits required to represent a number, we want one more bit than that so that all our non-negative numbers will start with 0 and all the negative numbers start with a 1. We need to modify that slightly to ensure that numbers of the form -2**n
will only get a single leading one bit, we do that by adding 1 to all the negative numbers when calculating the bit length.
To select the bits we want we need a bit mask of the appropriate length. If the bit length is 4, we want a mask of 1111 = 2**4 - 1
; we _could calculate it by using exponentiation, but it's more efficient to use bit shifting: (1 << bitlen) - 1
. We then do the bitwise AND operation n & mask
to select the bits we want. Fortunately, Python gives us a non-negative number when we perform such masking operations. :)
Finally we convert the resulting integer to a string using the .format
method. We use a nested format specification so we can dynamically specify the correct length of the output string. In
'{0:0{1}b}'.format(n & mask, bitlen)
the first 0 of the format spec says that we're converting the value of the 0 arg in the argument list (n & mask
), the :0{1}b
says to convert it to binary, padded with leading zeroes if necessary, using the value of the 1 arg in the argument list (bitlen
) as the total string length.
You can read about nested format specs in the Format String Syntax section of the docs:
A format_spec field can also include nested replacement fieldswithin it. These nested replacement fields may contain a field name,conversion flag and format specification, but deeper nesting is notallowed. The replacement fields within the format_spec aresubstituted before the format_spec string is interpreted. Thisallows the formatting of a value to be dynamically specified.