How to loop in the opposite order?

2024/11/24 8:42:49

I am a beginner programmer. Here is my code:

n = int(input())
from math import*
for i in range(n):print(n, "\t", log10(n))i = i + 1n = n - 1

Its output is:

10   1.0
9    0.9542425094393249
8    0.9030899869919435
7    0.8450980400142568    
6    0.7781512503836436
5    0.6989700043360189    
4    0.6020599913279624
3    0.47712125471966244
2    0.3010299956639812
1    0.0

I want it to be:

1    0.0
2    0.3010299956639812
3    0.47712125471966244
4    0.6020599913279624
5    0.6989700043360189
.
.
.
9    0.9542425094393249
10   1.0
Answer

First, you don't need to increment i, because it is the loop variable and is being set to each of 0 to 9 in turn.

Then your loop is printing n first. It starts at 10, and you subtract one from it each time, so you are getting the values in descending order. Try this:

for i in range(n):print i+1, "\t", log10(i+1)
https://en.xdnf.cn/q/120551.html

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