from selenium import webdriverdriver = webdriver.Chrome()
driver.set_page_load_timeout(7)def urlOpen(url):try:driver.get(url)print driver.current_urlexcept:return

Then I have URL lists and call above methods.

if __name__ == "__main__":urls = ['http://motahari.ir/', 'http://facebook.com', 'http://google.com']# It doesn't print anything# urls = ['http://facebook.com', 'http://google.com', 'http://motahari.ir/'] # This prints https://www.facebook.com/ https://www.google.co.kr/?gfe_rd=cr&dcr=0&ei=3bfdWdzWAYvR8geelrqQAw&gws_rd=sslfor url in urls:urlOpen(url)

The problem is when website 'http://motahari.ir/' throws Timeout Exception, websites 'http://facebook.com' and 'http://google.com' always throw Timeout Exception.

Browser keeps waiting for 'motahari.ir/' to load. But the loop just goes on (It doesn't open 'facebook.com' but wait for 'motahari.ir/') and keep throwing timeout exception

Initializing a webdriver instance takes long, so I pulled that out of the method and I think that caused the problem. Then, should I always reinitialize webdriver instance whenever there's a timeout exception? And How? (Since I initialized driver outside of the function, I can't reinitialize it in except)

You will just need to clear the browser's cookies before continuing. (Sorry, I missed seeing this in your previous code)

from selenium import webdriverdriver = webdriver.Chrome()
driver.set_page_load_timeout(7)def urlOpen(url):try:driver.get(url)print(driver.current_url)except:driver.delete_all_cookies()print("Failed")returnurls = ['http://motahari.ir/', 'https://facebook.com', 'https://google.com']for url in urls:urlOpen(url)

Output:

Failed
https://www.facebook.com/
https://www.google.com/?gfe_rd=cr&dcr=0&ei=o73dWfnsO-vs8wfc5pZI

P.S. It is not very wise to do try...except... without a clear Exception type, is this might mask different unexpected errors.