How to concisely represent if/else to specify CSS classes in Django templates

2024/10/13 5:19:19

In a Django template, I'd like to add CSS classes to a DIV based on certain "conditions", for example:

<div class="pkg-buildinfo {% if v.release.version == pkg.b.release.version %}active{% else %}inactive{% endif %} {% if v.release.version == project.latest.version %}latest{% else %}notlatest{% endif %}">

(note that v is a loop variable; the whole thing is inside a for loop)

The above adds CSS classes "active" or "inactive" and "latest" or "notlatest" based on two conditions.

This is however hard to read and verbose. I discovered that the with statement does not support assigning the value of expressions/conditions (as opposed to complex variables) which is a pity. Is there a better way to do this?

Answer

You could put that logic into your view instead, and create attributes on the object that are "active" or "inactive", etc. Then you only have to access the attributes in the template.

https://en.xdnf.cn/q/69571.html

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