I have a figure consisting of 3 subplots. I would like to locate the last subplot in the middle of the second row. Currently it is located in the left bottom of the figure. How do I do this? I cannot find the answer on stack overflow.

    fig, axes = plt.subplots(nrows=2, ncols=2, figsize=(13,10))ax= axes.flatten()ax[0].plot(vDT, np.cumsum(mWopt0[asset0,:])*percentage/iTT, label= 'COAL, c = 0')ax[0].legend()ax[0].set_title('Proportion in most invested stock')ax[1].plot(vDT, np.cumsum(mWopt01[asset01,:])*percentage/iTT, label= 'OINL, c = 0.1')ax[1].plot(vDT, np.cumsum(mWopt03[asset03,:])*percentage/iTT, label= 'OINL, c = 0.3')ax[1].plot(vDT, np.cumsum(mWopt05[asset05,:])*percentage/iTT, label= 'OINL, c = 0.5')ax[1].plot(vDT, np.cumsum(mWopt2[asset2,:])*percentage/iTT, label= 'OINL, c = 2')ax[1].plot(vDT, np.cumsum(mWopt5[asset5,:])*percentage/iTT, label= 'OINL, c = 5')ax[1].plot(vDT, np.cumsum(mWopt10[asset10,:])*percentage/iTT, label= 'OINL, c = 10')ax[1].legend()ax[1].set_title('Proportion in most invested stock')ax[2].plot(vDT, np.cumsum(mWopt01[index,:])*percentage/iTT, label= 'c = 0')ax[2].plot(vDT, np.cumsum(mWopt01[index,:])*percentage/iTT, label= 'c = 0.1')ax[2].plot(vDT, np.cumsum(mWopt03[ index,:])*percentage/iTT, label= 'c = 0.3')ax[2].plot(vDT, np.cumsum(mWopt05[index,:])*percentage/iTT, label= 'c = 0.5')ax[2].plot(vDT, np.cumsum(mWopt2[index,:])*percentage/iTT, label= 'c = 2')ax[2].plot(vDT, np.cumsum(mWopt5[index,:])*percentage/iTT, label= 'c = 5')ax[2].plot(vDT, np.cumsum(mWopt10[index,:])*percentage/iTT, label= 'c = 10')ax[2].legend()ax[2].set_title('Proportion invested in index')ax[0].set_ylabel('Expanding window weight')ax[1].set_ylabel('Expanding window weight')ax[2].set_ylabel('Expanding window weight')ax[3].remove()fig.autofmt_xdate(bottom=0.2, rotation=75, ha='right')plt.savefig('NSE_por_unrestricted_mostweightSI.jpg', bbox_inches='tight')plt.show()

matplotlib.gridspec.Gridspec solves your problem, and can be passed to plt.subplot. In this answer, you can see that a 4x4 grid can be used to position a plot in the middle easily:

import matplotlib.gridspec as gridspec
import matplotlib.pyplot as pltgs = gridspec.GridSpec(4, 4)ax1 = plt.subplot(gs[:2, :2])
ax1.plot(range(0,10), range(0,10))ax2 = plt.subplot(gs[:2, 2:])
ax2.plot(range(0,10), range(0,10))ax3 = plt.subplot(gs[2:4, 1:3])
ax3.plot(range(0,10), range(0,10))plt.show()

You can check out the demos for gridspec here: https://matplotlib.org/tutorials/intermediate/gridspec.html#sphx-glr-tutorials-intermediate-gridspec-py

The only problem is that you are using the fig, axes = pattern, which I don't see being typically used with Gridspec. You would need to refactor a bit.