I have a 2D array of dates of the form:

[Y Y Y ... ]
[M M M ... ]
[D D D ... ]
[H H H ... ]
[M M M ... ]
[S S S ... ]

So it looks like

data = np.array([[2015, 2015, 2015, 2015, 2015, 2015], # ...[   1,    1,    1,    1,    1,    1],[   1,    1,    1,    2,    2,    2],[  23,   23,   23,    0,    0,    0],[   4,    5,    5,   37,   37,   37],[  59,    1,    2,   25,   27,   29]
])

What would be the best way to convert this into one list of datetime objects?

import datetime
import numpy as npdata = np.array([[2015, 2015, 2015, 2015, 2015, 2015],[   1,    1,    1,    1,    1,    1],[   1,    1,    1,    2,    2,    2],[  23,   23,   23,    0,    0,    0],[   4,    5,    5,   37,   37,   37],[  59,    1,    2,   25,   27,   29]]
)# Transpose the data so that columns become rows.
data = data.T# A simple list comprehension does the trick, '*' making sure
# the values are unpacked for 'datetime.datetime'.
new_data = [datetime.datetime(*x) for x in data]print(new_data)

[datetime.datetime(2015, 1, 1, 23, 4, 59), datetime.datetime(2015, 1,1, 23, 5, 1), datetime.datetime(2015, 1, 1, 23, 5, 2),datetime.datetime(2015, 1, 2, 0, 37, 25), datetime.datetime(2015, 1,2, 0, 37, 27), datetime.datetime(2015, 1, 2, 0, 37, 29)]