I'm having a bit of difficulty figuring out what my next steps should be. I am using tastypie to create an API for my web application.

From another application, specifically ifbyphone.com, I am receiving a POST with no headers that looks something like this:

post data:http://myapp.com/api/
callerid=1&someid=2&number=3&result=Answered&phoneid=4

Now, I see in my server logs that this is hitting my server.But tastypie is complaining about the format of the POST.

{"error_message": "The format indicated'application/x-www-form-urlencoded' had no available deserializationmethod. Please check your formats and content_types on yourSerializer.", "traceback": "Traceback (most recent call last):\n\n File \"/usr/local/lib/python2.7/dist-packages/tastypie/resources.py\"

I also receive the same message when I try to POST raw data using curl, which I "believe" is the same basic process being used by ifbyphone's POST method:

curl -X POST --data 'callerid=1&someid=2&number=3&duration=4&phoneid=5' http://myapp.com/api/

So, assuming my problem is actually what is specified in the error message, and there is no deserialization method, how would I go about writing one?

#### Update ######

With some help from this commit ( https://github.com/toastdriven/django-tastypie/commit/7c5ea699ff6a5e8ba0788f23446fa3ac31f1b8bf ) I've been playing around with writing my own serializer, copying the basic framework from the documentation ( https://django-tastypie.readthedocs.org/en/latest/serialization.html#implementing-your-own-serializer )

import urlparse
from tastypie.serializers import Serializerclass urlencodeSerializer(Serializer):formats = ['json', 'jsonp', 'xml', 'yaml', 'html', 'plist', 'urlencode']content_types = {'json': 'application/json','jsonp': 'text/javascript','xml': 'application/xml','yaml': 'text/yaml','html': 'text/html','plist': 'application/x-plist','urlencode': 'application/x-www-form-urlencoded',}def from_urlencode(self, data,options=None):""" handles basic formencoded url posts """qs = dict((k, v if len(v)>1 else v[0] )for k, v in urlparse.parse_qs(data).iteritems())return qsdef to_urlencode(self,content): pass

This worked as expected when I edited my resource model to actually use the serializer class I created. This was not clear in the documentation.

class urlencodeSerializer(Serializer):formats = ['json', 'jsonp', 'xml', 'yaml', 'html', 'plist', 'urlencode']content_types = {'json': 'application/json','jsonp': 'text/javascript','xml': 'application/xml','yaml': 'text/yaml','html': 'text/html','plist': 'application/x-plist','urlencode': 'application/x-www-form-urlencoded',}def from_urlencode(self, data,options=None):""" handles basic formencoded url posts """qs = dict((k, v if len(v)>1 else v[0] )for k, v in urlparse.parse_qs(data).iteritems())return qsdef to_urlencode(self,content): passMyModelResource(ModelResoucre):class Meta:...serializer = urlencodeSerializer() # IMPORTANT