how to count the frequency of letters in text excluding whitespace and numbers? [duplicate]

2024/9/17 3:16:08

Use a dictionary to count the frequency of letters in the input string. Only letters should be counted, not blank spaces, numbers, or punctuation. Upper case should be considered the same as lower case. For example, count_letters("This is a sentence.") should return {'t': 2, 'h': 1, 'i': 2, 's': 3, 'a': 1, 'e': 3, 'n': 2, 'c': 1}

def count_letters(text):result = {}# Go through each letter in the textfor letter in text:# Check if the letter needs to be counted or notif letter not in result:result[letter.lower()] = 1# Add or increment the value in the dictionaryelse:result[letter.lower()] += 1return resultprint(count_letters("AaBbCc"))# Should be {'a': 2, 'b': 2, 'c': 2}print(count_letters("Math is fun! 2+2=4"))# Should be {'m': 1, 'a': 1, 't': 1, 'h': 1, 'i': 1, 's': 1, 'f': 1, 'u': 1, 'n': 1}print(count_letters("This is a sentence."))# Should be {'t': 2, 'h': 1, 'i': 2, 's': 3, 'a': 1, 'e': 3, 'n': 2, 'c': 1}
Answer
def count_letters(text):result = {}text = text.lower()# Go through each letter in the textfor letter in text:# Check if the letter needs to be counted or notif letter.isalpha() :# Add or increment the value in the dictionarycount = text.count(letter)result[letter] = countreturn resultprint(count_letters("AaBbCc"))
# Should be {'a': 2, 'b': 2, 'c': 2}print(count_letters("Math is fun! 2+2=4"))
# Should be {'m': 1, 'a': 1, 't': 1, 'h': 1, 'i': 1, 's': 1, 'f': 1, 'u': 1, 'n': 1}print(count_letters("This is a sentence."))
# Should be {'t': 2, 'h': 1, 'i': 2, 's': 3, 'a': 1, 'e': 3, 'n': 2, 'c': 1}
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