i have error eol while scanning string literal

2024/10/7 9:26:41

i dont know what is the problem im junior on python programer what happened on my code i study but i dnt understand this

#fungsi coveragedef coverage ():print("[1] Kota Besar)print("[2] Kota suburban)kota = input("PILIH KOTA")if int (kota) == 1:frekuensi =  input("Masukan Frekuensi : )if int (frekuensi)<300;htower = float(input("input Tinggi tower : "))hpengguna =float (input("input Tinggi Pengguna : "))pathloss = float (input ("input Median Pathloss : "))logahre = math.log(1.54 * hpengguna, 10)**2)ahre =  8.29 * logahre - 1.1logfrek = math.log(frekuensi, 100loghte = math.log(htower, 10)pangkat = (-69.55-26.16*logfrek+13.82*loghte+ahre+pathloss)/44.9-(6.55 * loghte) print ("%s"%pangkat)   

EOL while scanning literal

Answer

So many syntax issues in your code. Here is a working code, all are very minor things like double quotes, semi column, brackets

#fungsi coveragedef coverage ():print("[1] Kota Besar")print("[2] Kota suburban")kota = input("PILIH KOTA")if int (kota) == 1:frekuensi =  input("Masukan Frekuensi : ")if int (frekuensi)<300:htower = float(input("input Tinggi tower : "))hpengguna =float (input("input Tinggi Pengguna : "))pathloss = float (input ("input Median Pathloss : "))logahre = math.log(1.54 * hpengguna, 10)**2ahre =  8.29 * logahre - 1.1logfrek = math.log(frekuensi, 100)loghte = math.log(htower, 10)pangkat = (-69.55-26.16*logfrek+13.82*loghte+ahre+pathloss)/44.9-(6.55 * loghte) print ("%s"%pangkat) 
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