Given a string, say s='135' and a list, say A=['1','2','3','4','5','6','7'], how can I separate the values in the list that are also in 's' (a digit of s) from the other elements and concatenate these other elements. The output in this example should be: A=['1','2','3','4','5','67']. Another example: s='25' A=['1','2','3','4','5','6','7'] output: A=['1','2','34','5','67']

Is there a way of doing this without any import statements (this is so that I can get a better understanding of Python and how things work)?

I am quite new to programming so any help would be appreciated!

(Please note: This is part of a larger problem that I am trying to solve).

You can use itertools.groupby with a key that tests for membership in your number (converted to a string). This will group the elements based on whether they are in s. The list comprehension will then join the groups as a string.

from itertools import groupbyA=['1','2','3','4','5','6','7']
s=25
# make it a string so it's easier to test for membership
s = str(s)["".join(v) for k,v in groupby(A, key=lambda c: c in s)]
# ['1', '2', '34', '5', '67']

Edit: the hard way

You can loop over the list and keep track of the last value seen. This will let you test if you need to append a new string to the list, or append the character to the last string. (Still itertools is much cleaner):

A=['1','2','3','4','5','6','7']
s=25
# make it a string
s = str(s)output = []
last = Nonefor c in A:if last is None:output.append(c)elif (last in s) == (c in s):output[-1] = output[-1] + celse:output.append(c)last = coutput # ['1', '2', '34', '5', '67']