I have task where I need to print the occurrence and count and non-occurrence and count

import resequence = '1222311'm = re.search(r'(\d)\1+',sequence)print(m)    

Exptected output :

(1, 1) (3, 2) (1, 3) (2, 1)

In sequence need to check and print

 (cnt , val) -> 1222311 -> 1 as come only once -> (1,1) (cnt,number)

You can use re.finditer to get start/end index of match and then construct your output (regex101):

import resequence = '1222311'out = [(m.end() - m.start(), int(m.group(1))) for m in re.finditer(r'(\d)\1*', sequence)]
print(out)

Prints:

[(1, 1), (3, 2), (1, 3), (2, 1)]