I want a URL something like this:

/(category)/(post-slug)

On the link this is what I have:

{% url blog.category blog.slug %}

and for the url.py:

url(r'^(I DON"T KNOW WHAT TO PUT ON THIS PART TO GET THE CATEGORY)/(?P<slug>[0-9A-Za-z._%+-]+)', views.post, name='post'),

thanks

EDIT: This is what I have now: Still have NoReverseMatch error at /

urls.py

 url(r'^(?P<category>[0-9A-Za-z._%+-]+)/(?P<slug>[0-9A-Za-z._%+-]+)$', views.post, name='post'),

index.html

<a href="{% url blog.category blog.slug %}">

views.py

def post(request, slug, category):try:blog = Blog.objects.get(slug=slug)except Blog.DoesNotExist:raise Http404('This post does not exist')return render(request, 'parts/post.html', {'blog': blog,})

Firstly, your URL tag needs the name of the pattern you are reversing as the first argument:

{% url 'post' blog.category blog.slug %}

or if you are using a namespace, something like:

{% url 'blog:post' blog.category blog.slug %}

You haven't shown your views or models, so we can only guess what your URL pattern should be. I'm not sure why you find the category confusing - you just need to choose a name for the group (e.g. category_slug), and the regex for the group (you might be able to use the same one as you use for slug). That would give you:

url(r'^(?P<category_slug>[0-9A-Za-z._%+-]+)/(?P<slug>[0-9A-Za-z._%+-]+)$'

Note that there should be a dollar on the end of the regex.