The parameter is a string. Check whether it forms a secure password.A password is safe if

• there is at least a lowercase letter in it, and
• there is at least one capital letter in it, and
• there is at least one digit in it, and
• there is at least one special character (+, -, *, /,. or @) in it, and
• it counts at least 8 characters, and
• it has a maximum of 20 characters, and
• there are no three equal consecutive characters in it (eg 'a7XXX @ fda' is invalid because of the XXX), and
• no group of three characters occurs multiple times (eg 'XYZ.1a.XYZ' is invalid because XYZ appears twice).

I tried:

regex = [r'^.{8,20}$', r'[a-z]+', r'[A-Z]+', r'\d+', r'[-+*/.@]', r'(.)(.)(.)(\1\2\3)']return all(re.search(pas, password) for pas in regex)

You can use lookahead assertions:

import rereg=re.compile(r"(?=.*[a-z]+.*)(?=.*[A-Z]+.*)(?=.*\d+.*)(?=.*[-\+\*\./@]+.*)(?!.*(.)\1\1.*)(?!.*(.{3}).*\2.*).{8,20}$")pwds=[ "aA3@5678", "aA3@567","abcdefghABCDEFGH+-*3","abcdefghABCDEFGH+-*3X","aA3@555678","aA3@@@5678", "a_A3Q_5678*A3Q", "a_A+Q_3.14/-5678*A+Q"]for pwd in pwds:m=reg.fullmatch(pwd)print("{}: {}".format(pwd,"good" if m else "bad"))