I'm new with python. Here is my csv file :

data;data;name surname; data; data
data;data;name surname; data; data
data;data;name surname; data; data
data;data;name surname; data; data

The thing that I want to do is to insert ";" to make name and surname 2 columns like that :

data;data;name;surname; data; data
data;data;name;surname; data; data
data;data;name;surname; data; data
data;data;name;surname; data; data

But the hard thing is sometimes there is more than one space, like that :

data;data;name surname surname2; data
data;data;name surname surname2 surname3; data 

And I just want to replace the first spaces, not all like that :

data;data;name;surname surname2; data
data;data;name;surname surname2 surname3; data 

Here is my code but it replaces every space:

def modify_rows():with open("result2.csv","rb") as source:rdr= csv.reader(source, delimiter=';')with open("result3.csv","wb") as result:wtr= csv.writer(result,delimiter=';')for r in rdr:rowname = r[3].replace(' ', ';')wtr.writerow((r[0],r[1],rowname,r[2]))    

Hope I can find help.

You can tell Python's split() to stop after a given number of matches by passing a maxsplit parameter. So in your case you just need to split after the first space as follows:

import csvwith open('input.csv', 'rb') as f_input, open('output.csv', 'wb') as f_output:csv_output = csv.writer(f_output, delimiter=';')for row in csv.reader(f_input, delimiter=';'):# Skip empty linesif len(row) > 3:try:name, surname = row[2].split(' ', 1)except ValueError as e:# No surnamename, surname = row[2], ''row[2] = namerow.insert(3, surname)csv_output.writerow(row)

So for an input with:

data;data;name surname1 surname2;data;data
data;data;name surname;data;data
data;data;name surname;data;data
data;data;name surname;data;data

You would get:

data;data;name;surname1 surname2;data;data
data;data;name;surname;data;data
data;data;name;surname;data;data
data;data;name;surname;data;data