I have two lists:
a - dictionary which contains keywords such as ["impeccable", "obvious", "fantastic", "evident"] as elements of the list
b - sentences which contains sentences such as ["I am impeccable", "you are fantastic", "that is obvious", "that is evident"]
The goal is to use the dictionary list as a reference.
The process is as follows:
- Take an element for the
sentences list and run it against each element in the dictionary list. If any of the elements exists, then spit out that sentence to a new list
- Repeating step 1 for each of the elements in the
sentences list.
Any help would be much appreciated.
Thanks.
Below is the code:
sentences = "The book was awesome and envious","splendid job done by those guys", "that was an amazing sale"dictionary = "awesome","amazing", "fantastic","envious"##Find Matches
for match in dictionary:if any(match in value for value in sentences):print match
Now that you've fixed the original problem, and fixed the next problem with doing the check backward, and renamed all of your variables, you have this:
for match in dictionary:if any(match in value for value in sentences):print match
And your problem with it is:
The way I have the code written i can get the dictionary items but instead i want to print the sentences.
Well, yes, your match is a dictionary item, and that's what you're printing, so of course that's what you get.
If you want to print the sentences that contain the dictionary item, you can't use any, because the whole point of that function us to just return True if any elements are true. It won't tell you which ones—in fact, if there are more than one, it'll stop at the first one.
If you don't understand functions like any and the generator expressions you're passing to them, you really shouldn't be using them as magic invocations. Figure out how to write them as explicit loops, and you will be able to answer these problems for yourself easily. (Note that the any docs directly show you how to write an equivalent loop.)
For example, your existing code is equivalent to:
for match in dictionary:for value in sentences:if match in value:print matchbreak
Written that way, it should be obvious how to fix it. First, you want to print the sentence instead of the word, so print value instead of match (and again, it would really help if you used meaningful variable names like sentence and word instead of meaningless names like value and misleading names like match…). Second, you want to print all matching sentences, not just the first one, so don't break. So:
for match in dictionary:for value in sentences:if match in value:print value
And if you go back to my first answer, you may notice that this is the exact same structure I suggested.
You can simplify or shorten this by using comprehensions and iterator functions, but not until you understand the simple version, and how those comprehensions and iterator functions work.