I need to find a way to count how many times each number from 0 to 9 appears in a random matrix created using np.random.randint()

import numpy as np
p = int(input("Length of matrix: "))
m = np.random.randint(0,9,(p,p))
print(m)

For example if length of matrix = 4

• [[3 4 6 5] [3 4 4 3] [4 2 4 8] [6 8 2 7]]

How many times does the number 4 appear? It should return 5.

You should be able to get this pretty simply:

list(m.flatten()).count(x)

Another option which is probably faster, is to use the numpy builtin count_nonzero():

np.count_nonzero(m == x)

Hooray builtin functions.