Question 1

i 've the following folder structure

src\BAT\templates\admin\base.html
src\BAT\media\base.css
src\BAT\media\admin-media\base.css

settings.py

MEDIA_ROOT = os.path.join( APP_DIR, 'media' )
MEDIA_URL = '/media/'
ADMIN_MEDIA_PREFIX = '/admin-media/'
TEMPLATE_DIRS = (os.path.join( APP_DIR, 'templates' )
)
INSTALLED_APPS = ('django.contrib.auth','django.contrib.contenttypes','django.contrib.sessions','django.contrib.sites','django.contrib.messages','django.contrib.admin','django.contrib.admindocs',
)

urls.py

urlpatterns = patterns('',(r'^admin/doc/', include('django.contrib.admindocs.urls')),(r'^admin/', include(admin.site.urls)),(r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}),)

I need to get both the CSS files in my application. my base.html contains

<head>
<title>{% block title %}{% endblock %}</title>
<link href="{{ MEDIA_URL }}css/base.css" rel="stylesheet" type="text/css" />
<link href="{{ MEDIA_URL }}{{ADMIN_MEDIA_PREFIX}}css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="{% block stylesheet %}{% load adminmedia %}{% admin_media_prefix %}css/base.css{% endblock %}" />
{% block extrastyle %}{% endblock %}
<!--[if lte IE 7]><link rel="stylesheet" type="text/css" href="{% block stylesheet_ie %}{% load adminmedia %}{% admin_media_prefix %}css/ie.css{% endblock %}" /><![endif]-->
{% if LANGUAGE_BIDI %}<link rel="stylesheet" type="text/css" href="{% block stylesheet_rtl %}{% admin_media_prefix %}css/rtl.css{% endblock %}" />{% endif %}
<script type="text/javascript">window.__admin_media_prefix__ = "{% filter escapejs %}{% admin_media_prefix %}{% endfilter %}";</script>
{% block extrahead %}{% endblock %}
{% block blockbots %}<meta name="robots" content="NONE,NOARCHIVE" />{% endblock %}
</head>

I want to get the following output for URL http://localhost:8000/admin

<head>
<title>Site administration | My site admin</title>
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link href="/media/admin-media/css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="/media/admin/css/base.css" />
<link rel="stylesheet" type="text/css" href="/media/admin/css/dashboard.css" />

But I always getting

<head>
<title>Site administration | My site admin</title>
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="/admin-media/css/base.css" />
<link rel="stylesheet" type="text/css" href="/admin-media/css/dashboard.css" />

while direct accessing http://localhost:8000/admin-media/css/base.css shows css file from Python site-packages/django/contrib/admin/media/css

while direct accessing http://localhost:8000/media/admin-media/css/base.css shows css file from src/media/admin-media/css/

while direct accessing http://localhost:8000/media/css/base.css shows css file from src/media/css/

Question 2

Important for Django 1.4 and newer (see here):

Starting in Django 1.4, the admin’s static files also follow this convention, to make the files easier to deploy. In previous versions of Django, it was also common to define an ADMIN_MEDIA_PREFIX setting to point to the URL where the admin’s static files live on a Web server. This setting has now been deprecated and replaced by the more general setting STATIC_URL. Django will now expect to find the admin static files under the URL <STATIC_URL>/admin/.

Previous answer, for older Django releases:

ADMIN_MEDIA_PREFIX is meant to be an absolute URL prefix, it has nothing to do with the MEDIA_URL - both can point to completely different points. Admittedly, the (bad) choice of "_PREFIX" in the name somewhat suggests that.

So, instead of {{ MEDIA_URL }}{{ADMIN_MEDIA_PREFIX}}css/base.css it must be {% admin_media_prefix %}css/base.css. And then you have to ensure that the web server serves the admin media files on '/admin-media/'.

Note that I used the admin_media_prefix tag above, which needs {% load adminmedia %} at the beginning of the template. The regular media context processor only gives you the MEDIA_URL variable, unfortunately.

In order to override the vanilla admin media serving, try something like this in your URLconf:

# A handy helper function I always use for site-relative paths
def fromRelativePath(*relativeComponents):return os.path.join(os.path.dirname(__file__), *relativeComponents).replace("\\","/")[...]url("^admin-media/(?P<path>.*)$","django.views.static.serve",{"document_root": fromRelativePath("media", "admin-media")})

Django Admin Media prefix URL issue

Related Q&A

lazy processpoolexecutor in Python?

error occurs when installing cryptography for scrapy in virtualenv on OS X [closed]

Can Python do DI seamlessly without relying on a service locator?

Producing pdf report from python with bullet points

Converting bits to bytes in Python

Install python package from private pypiserver

Matplotlib Table- Assign different text alignments to different columns

How would I make a random hexdigit code generator using .join and for loops?

Multiline python regex

How can I process xml asynchronously in python?