How can I subplot 'pie1' in 'fig', so it be located at 'the first' position. this is how I am doing it but it doesn't work out

    import pandas as pdimport numpy as npimport seaborn as snsimport plotly.offline as pypimport plotly.graph_objs as gofrom plotly import toolsimport plotly.plotly as pyfrom plotly.offline import iplot,init_notebook_modefrom IPython.core.display import HTMLimport plotly.iodf1=pd.read_excel('file.xlsx',sheet_name='sheet1',index=False)con_pivot=pd.pivot_table(con,index='Category',values=('Payment'),aggfunc='sum',margins=True,margins_name='Total')fig = tools.make_subplots(rows=2, cols=2, subplot_titles=('The first','3','2','4'))pie1=go.Pie(labels=con_pivot.index,values=con_pivot.values)fig.append_trace(pie1,1,1)pyo.plot(fig)

Any help help will be appreciated. Thank you

The way to achieve the side by side pie charts using the make_subplots function from plotly would be the following (Many thanks to @Oysiyl for the input data):

from plotly.subplots import make_subplots
import plotly.graph_objects as go
from plotly.offline import plotfig = make_subplots(rows=1, cols=2, specs=[[{"type": "pie"}, {"type": "pie"}]])fig.add_trace(go.Pie(values=[16, 15, 12, 6, 5, 4, 42],labels=["US", "China", "European Union", "Russian Federation","Brazil", "India", "Rest of World"],domain=dict(x=[0, 0.5]),name="GHG Emissions"), row=1, col=1)fig.add_trace(go.Pie(values=[27, 11, 25, 8, 1, 3, 25],labels=["US", "China", "European Union", "Russian Federation","Brazil", "India", "Rest of World"],domain=dict(x=[0.5, 1.0]),name="CO2 Emissions"),row=1, col=2)plot(fig)