How to traverse a high-order range in Python? [duplicate]

2024/11/16 5:51:28

In python, we can use range(x) to traverse from 0 to x-1. But what if I want to traverse a high-order range? For example, given (a, b), I want to traverse all (x1, x2) such that 0 <= x1 < a, 0<= x2 < b. If the dimension is fixed, then it's easy, say it's k-dimension (in the example I gave, k is 2), then we can simply hard-code k loops to achieve it, but how about when the dimension is also a variable? Is there any elegant pythonic way to handle this?

Answer

Use itertools.product:

from itertools import productfor x, y, z in product(range(a), range(b), range(c)):print( (x,y,z) )

With a variable number of dimensions:

limits = [5, 3, 7, 6]for v in product(*(range(n) for n in limits)):print(v)
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