I am using Cython in jupyter notebook.

As I know, Cython compiles def functions.

But when I want to call function with global variable it doesn't see it.

Are there any method to call function with variable?

one1 = 1
%%cython
cimport numpy as np
cdef nump(number1):return number1 + 1
nump(one1)

****This is sample code, to show moderators

In an Ipython session I can do:

In [2]: %load_ext Cython
In [3]: one = 1
In [4]: %%cython...: def foo(num):...:    return num + 1...: 
In [5]: foo(one)
Out[5]: 2

That is I define a cython function, but call it from Python with the global variable.

If I define the function with cdef I need to invoke it with a def function. fooc is not visible from Python.

In [9]: %%cython...: cdef fooc(num):...:    return num + 2...: def foo_call(num):...:    return fooc(num)...: 
In [10]: foo_call(one)
Out[10]: 3

If I attempt to use one from within the cython file (magic cell) I get an error, the equivalent of a Python NameError

In [8]: %%cython...: cdef fooc(num):...:    return num + 2...: print(fooc(one))...: Error compiling Cython file:
...
/home/paul/.cache/ipython/cython/....: undeclared name not builtin: one

The ipython session variable one is not visible from within the magic cell.

Working from @DavidW's answer, this import works:

In [14]: %%cython...: from __main__ import one...: cdef fooc(num):...:    return num + 2...: print(fooc(one))...: 
3

This fooc is not accessible from Python.

Note that the import uses the value of one at compile time.

In [22]: %%cython...: from __main__ import one...: cdef fooc(num):...:    return num + 20...: def fooc_call():...:    print(fooc(one))...: ...: 
In [23]: fooc_call()
21
In [24]: one=343           # new value
In [25]: fooc_call()        # no change
21
In [26]: foo_call(one)     # uses the current value
Out[26]: 345