How to check with more RegEx for one address in python using re.findall()

Ex: I want to apply the below regex rules

 # need to get addresstxt = "hello user 44 West 22nd Street, New York, NY 12345 from"    regexp = "[0-9]{1,3} .+, .+, [0-9]{5}"regexp1 = "[0-9]{1,3} .+, .+, [A-Z]{2} [0-9]{5}"regexp2 = "[0-9]{1,3} .+, .+, [A-Z]{2} [0-9]{9}"    re.findall(regexp, regexp1, regexp2, txt)

is this correct? I am getting error of this code

Finally I got answer from here

How to combine multiple regex into single one in python?

Working fine this

import re
re1 = r'\d+\.\d*[L][-]\d*\s[A-Z]*[/]\d*'
re2 = '\d*[/]\d*[A-Z]*\d*\s[A-Z]*\d*[A-Z]*'
re3 = '[A-Z]*\d+[/]\d+[A-Z]\d+'
re4 = '\d+[/]\d+[A-Z]*\d+\s\d+[A-z]\s[A-Z]*'sentences = [string1, string2, string3, string4]
generic_re = re.compile("(%s|%s|%s|%s)" % (re1, re2, re3, re4)).findall(sentence)